Question

The perimeter of a triangle is x2 - x - 2 and two of its sides are x - x + 1 and x2 - 2x + 1. Find the third side of the triangle.​

Answer 1

Given:-

The perimeter of a triangle is x2 - x - 2 and two of its sides are x - x + 1 and x2 - 2x + 1. Find the third side of the triangle.

To Find:-

Third side of the triangle.

Formula:-

$x + x + x + x$

Solution:-

$let \: the \: third \: side \: be \: y. \\ perimeter \: = \: sum \: of \: all \: the \: 3 \: sides \\ {x}^{2} - 2x + 1 + {3x}^{2} - 5x + 3 + y = {6x}^{2} - 4x + 9 \\ {x}^{2} + {3x}^{2} + {6x}^{2} 2x - 5x + 4 + 1 + 9 + y = 0 \\ {2x}^{2} - 3x + 10 + y = 0 \\ {2x}^{2} + 3x - 10 + y = 0 \\ {2x}^{2} + 3x - 10 - y = 0 \\ y = {2x}^{2} + 3x - 10$

Thanks!!!Σ ◕ ◡ ◕

❥Hope it helps u

❥Mark me as brainliest