The perimeter of a triangle is (x²y+10) units . One of the side is of length (x²-4) units and another sides is (3-2x²y)units . Find the length of the third side.
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Correct Question :
The perimeter of a triangle is (x²y+10) units . One of the side is of length (x²y - 4) units and another sides is (3-2x²y)units . Find the length of the third side.
Given :
• One side's length = x²y - 4
• Another side's length = 3 - 2x²y
• Perimeter of the ∆ = x²y + 10
To Find :
• Length of the third side.
Solution :
Let the third side be a
We know that,
★ Perimeter = Sum of all sides
→ x²y + 10 = (x²y - 4) + (-2x²y + 3) + a
→ x²y + 10 = x²y - 4 - 2x²y + 3 + a
→ x²y + 2x²y - x²y + a = - 10 - 4 + 3
→ 2x²y + a = -11
→ a = 2x²y + 11
Third side of the triangle = 2x²y + 11.
Answered by
1
Answer:
2x^2y +11.
Step-by-step explanation:
is the correct answer
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