the perimeter of a triangle whose sides are 2y+3z, z-y, 4y-2z is
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(2y+3z)+(z-y)+(4y-2z)
= 5y+2z
= 5y+2z
Answered by
1
perimeter of triangle =a+b+c
=2y+3z+z-y+4y-2z
=5y+2z
=2y+3z+z-y+4y-2z
=5y+2z
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