The perimeter of a triangle with vertices (0, 4), (0, 0) and (3, 0) is
(A) 5 (B) 12 (C) 11 (D) 7 + SQRT5
NCERT Class X
Mathematics - Exemplar Problems
Chapter _COORDINATE GEOMETRY
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(b)12 because
when we draw this triangle on the graph we have
base=3 , perpendicular=4 and hypotunose=?
by pythagorus theorem
Hsquare=base square + perpendicular square
=9+16
H=5
perimeter=3+4+5
=12
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