The perimeter of a triangle with vertices (0,4), (0.0) and (3,0) is:
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Answer:
12 units
Step-by-step explanation:
Let A,B &C be the vertices of a triangle.
So,A=(0,4) B=(3,0) & C=(0,0)
NOW, applying distance formula find the distance of AB,BC and AC
You will get,
AB=5units BC=3units & AC=4units
Therefore,
PERIMETER= AB+BC+AC=5+3+4=12units
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