Question

The perimeter of a triangle with vertices (0, 4), (0, 0) and (3, 0) is
(a) 5 
(b) 12 
(c) 11 
(d) 7 + √5​

Answer 1

Answer:

12

Explan

$\sqrt (0 - 0) ^{2} + (0 - 4) {}^{2} \sqrt16 = 4 \\ \sqrt{(3 - 0} ) ^{2} + (0 - 0) {}^{2} = \\ \sqrt{9} = 3 \\ \sqrt{(0 - 3)} {}^{2} + (4 - 0) {}^{2} = \sqrt{25 = 5}$

perimeter of ABC =AB+BC+CA =4+3+5=12