Question

The perimeter of a
triangles
field
420m. and its sides are in the 6:7:8
find the area of the triangular
field.​

Answer 1

Answer:

perimeter = a+b+c = 420m

let sides = 6x+7x+8x

AtoQ

6x+7x+8x = 420

21x=420

x=420/21

x= 20

1st side = 6×20=120m

2nd side = 7×20 = 140m

3rd side = 8×20=160m

by heron's formula :

Sides are 120,140 and 160 m

Area = √S(S−A)(S−B)(S−C)

semi peri = 120+140+160/2 = 420/2 =210 m

A= √210(210−120)(210−140)(210−160)

=2100 √15 sq. m

Step-by-step explanation:

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