Question

the perimeter of a triangular field is 135 cm it's sides are in ratio 25:17:12 find the area of the triangle​

Answer 1

Answer:

Answer

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Perimeter = 135 cm

Let ratio = x

a=25x

b=17x

c=12x

a+b+c=135

25x+17x+12x=135

54x=135

x=

54

135

x=

18

45

x=

2

5

a=25×

2

5

=

2

125

b=17×

2

5

=

2

85

c=12×

2

5

=

2

60

Semiperimeter:

2

1

[

2

125

+

2

85

+

2

60

]

=

2

1

×

2

1

[125+85+60]

=

4

1

(270)

=

2

135

s−a=

2

135

−

2

125

=

2

10

=5

s−b=

2

135

−

2

85

=

2

50

=25

s−c=

2

135

−

2

60

=

2

75

Area=

s(s−a)(s−b)(s−c)

=

2

135

(

2

10

)(

2

50

)(

2

75

)

=

4

1

135×10×50×75

=

4

1

×2250

=562.50cm

2

.

Answer 2

Answer:

Let the sides of the triangular field be 25x, 17x and 12x. As, perimeter = 540 m 25x +17x +12x = 540 54x = 540 x = 540/54 x = 10 So, the sides are 250 m, 170 m and 120 m. Now, semi-perimeter, s = (250+170+120)/2 = 540/2 = 270 m So, area of the filed