History, asked by subhram501, 9 months ago

The perimeter of a triangular field is 240 dm. If two of its sides are 50 dm and 78 dm, find
of the perpendicular on the side of length 50 dm from the opposite vertex. Calculate also
watering it at 2.75 per 100 m².​

Answers

Answered by ꜱɴᴏᴡyǫᴜᴇᴇɴ
5

Explanation:

Perimeter of the triangle = 240 dm

Two sides (given) = 78 dm and 50 dm

Third side of the triangle = 240 - (78 + 50)

= 240 dm - 128 dm

= 112 dm

s = (a + b + c)/2

= (78 + 50 + 112)/2

= 240/2

s = 120 dm

Area of the triangle = √s(s - a)(s - b)(s - c)

⇒ √120 (120 - 50)(120 - 78)(120 - 112)

⇒ √120*70*42*8

⇒ √2822400

Area of the triangle = 1680 sq dm

Now,

Area of the triangle = 1/2*base*height

Height = 2*area/base

⇒ (2*1680)/50

⇒ 336/5

height = 67.2 dm

Plz Mark as BRAINLIEST

Answered by piyushxd26
2

Answer:

height = 67.2 dm

Explanation:

Perimeter of the triangle = 240 dm

Two sides (given) = 78 dm and 50 dm

Third side of the triangle = 240 - (78 + 50)

= 240 dm - 128 dm

= 112 dm

s = (a + b + c)/2

= (78 + 50 + 112)/2

= 240/2

s = 120 dm

Area of the triangle = √s(s - a)(s - b)(s - c)

⇒ √120 (120 - 50)(120 - 78)(120 - 112)

⇒ √120*70*42*8

⇒ √2822400

Area of the triangle = 1680 sq dm

Now,

Area of the triangle = 1/2*base*height

Height = 2*area/base

⇒ (2*1680)/50

⇒ 336/5

height = 67.2 dm

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