Question

the perimeter of a triangular field is 240 m its two sides are 78 m and 50 m then find area of triangular field

Answer 1

Perimeter of triangle = sym of all sides
240 = 78 + 50 + a
240 = 128 + a
a = 240 - 128
= 112
s = 240/2
= 120
area of triangle = √s(s-a)(s-b) (s-c)

= √120(120 - 78)(120 - 50)(120 - 112)
= √120(42)(70)(8 )
= √2822400
= 1680m square