Question

the perimeter of a triangular field is 240m and its sides are in the ratio of 3:4:5. find the area of the triangle. Also find the cost of ploughing the field at rs.15 per m^2.

Pls answer fast​

Answer 1

GIVEN :-

The perimeter of a triangular field is 240 m.

Ratio of sides of triangular field are 3:4:5.

TO FIND :-

the area of the triangular field.

Cost of ploughing.

SOLUTION :-

Let the ratio constant be "x".

✮ Sides of Triangular Field,

➳ a = 3x.

➳ b = 4x.

➳ c = 5x.

✮ Semi - Perimeter of Triangular Field,

➳ Semi - Perimeter = perimeter/2

➳ Semi - Perimeter = 240/2

➳ Semi - Perimeter = 120 m.

✮ Sides of Triangular Field,

As we know that the semi perimeter of a triangle is

given by,

➵ Semi - perimeter (a + b + c)/2

➵ 120 m = (3x + 4x + 5x)/2

➵ 120 = 12x/2

➵ (120 × 2)/12 = x

➵ x = 20.

Now substitute the value of x in the sides of triangle,

➳ a = 3x = 60 m.

➳ b = 4x = 80 m.

➳ c = 5x = 100 m.

✮ Area of triangular field,

As we know that the area of triangle is given by,

✯ Area ∆ = √{s(s - a)(s - b)(s - c)}

➟ Area ∆ = √{120(120 - 60)(120 - 80)(120 - 100)}

➟ Area ∆ = √{120 × 60 × 40 × 20}

➟ Area ∆ = √5760000

➟ Area ∆ = 2400 m².

✮ Cost of pluoghing the field,

➳ Cost = Area × Rate.

➳ cost = 2400 × 15

➳ cost = Rs. 36000.

Answer 2

Answer:

Area=2400msquare

cost of ploughing=$36000