Question

The perimeter of a triangular field is 300 m and its-sides are in the ratio 5:12: 13. Find the area of the field. Also, find the cost of ploughing the field at * 5 per m².


(Those who answer the right answer with explanation will be marked as brainlist.)​

Answer 1

p= 300

let sides be=5x,12x,13x

300= 5x+12x+13x

300= 30x

x=300/30

x= 10 m

5x= 5× 10 = 50 m

12x= 12× 10= 120 m

13x= 13×10= 130 m

now you can find area by formula 1/2×base× height

and then just multiply the area by 5 to find the cost

Answer 2

Answer:

• The sides of triangles are 50m, 120m and 130 m.
• The cost of ploughing the field at  =  Rs 15000 .

Step-by-step explanation:

Given:

The perimeter of a triangular field is 300 m

If common multiple is x.

then its sides are 5x, 12x and  13x.

Find the area of the field.

Also, find the cost of ploughing the field at   5 per m².

Formula :

The perimeter of triangle = Addition of all three sides

5x + 12x + 13x = 300

(5 + 12 + 13)x = 300

30x = 300

x = 10

So, sides of triangles are 50m, 120m and 130 m.

And

If perimeter is 300 then semi perimeter (s) = 150 m

Area of triangle =

$\sqrt{s(s-a)(s-b)(s-c)} \\= \sqrt{150 (150 - 50)(150 -120)(150 -130)} \\=\sqrt{150 \times 100 \times 30 \times 20} \\=\sqrt{9000000} \\= 3000 sq. m$

The cost of ploughing the field at  = 3000 × 5  = Rs 15000  .