Math, asked by ash09954, 11 months ago

The perimeter of a triangular field is 420 m. and it's sides are in the ratio 6:7:8. Find the area of the triangular field.

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Answers

Answered by rishabh4163
0

Step-by-step explanation:

Perimeter = sum all sides

420 = 6x + 7x + 8x

420 = 21x

420/21 = x

Answered by Anonymous
2

Solution

explanation

Given, perimeter of a triangular field is 420 m and its sides are in the ratio 6:7:8.

Let sides of a triangular field be a = 6x, b = 7x and c = 8x.

Perimeter of a triangular field, 2s = a + b + c ⇒ 420 = 6x + 7x + 8x ⇒ 420 = 21x

Perimeter of a triangular field, 2s = a + b + c ⇒ 420 = 6x + 7x + 8x ⇒ 420 = 21x⇒ x = 420/21 = 20 m.

answer :- 20 metre

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