Question

The perimeter of a triangular field is 420m & it's aides are in the ratio 6:7:8. Find the area if the triangular field. Also find the area of a cyclic rhombus of each side 3cm.
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Answer 1

Answer:

Given, perimeter of a triangular field is 420 m and its sides are in the ratio 6:7:8.

Let sides of a triangular field be a = 6x, b = 7x and c = 8x.

Perimeter of a triangular field, 2s = a + b + c ⇒ 420 = 6x + 7x + 8x ⇒ 420 = 21x

⇒ x = 420/21 = 20 m.

Step-by-step explanation:

Answer 2

so perimeter of triangle,

$a + b + c \\ 6x + 8x + 7x = 420 \\ 21x = 420 \\ 420 \div 21 = \\ 20m$

hope it help