The perimeter of a triangular field is 450 m and its sides are in the ratio 13 12: 5. Find the area of the triangle.
Answers
Answer :-
- 6750m².
Given :-
- The perimeter of a triangular field is 450m and its sides are in the ratio 13 : 12 : 5
To Find :-
- Area of the triangle
Solution :-
Put x in the ratio
Sides are
13x
12x
5x
As we know that
Perimeter of a triangle is sum of all sides
Now,
13x + 12x + 5x = 450
→ 30x = 450
→ x = 450/30
→ x = 15
Put the value of x in the ratio
- 13x = 13 × 15 = 195
- 12x = 12 × 15 = 180
- 5x = 5 × 15 = 75
- a = 195
- b = 180
- c = 75
- Semi perimeter (S) = 450/2 = 225
As we know that
Area of a triangle is :-
- √ s (s - a) (s - b) (s - c)
According to question :-
√ 225 × (225 - 195) × (225 - 180) × (225 - 75)
→ √ 225 × 30 × 45 × 150
→ √ 45562500
→ 6750m²
Hence, the area of the triangle is 6750m².
Answer :
Given :
• Perimeter of triangular field = 450 m
• Sides of field are in ratio of 13 : 12 : 5
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To Find :
• Area of triangular field
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Solution :
• Let the side be x , then the sides become 13x , 12x and 5x .
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• SIDES OF TRIANGLE ARE :
➪ 13x = 13(15) = 195 m
➪ 12x = 12(15) = 180 m
➪ 5x = 5(15) = 75 m
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★ Now , we have to find area :
• We will be using Heron's formula -
☯︎ Here , a = 195 , b = 180 , c = 75
Now , Semi perimeter =
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