Question

The perimeter of a triangular field is 540 m and its side are in ratio 25 : 17 : 12. Find the area of the triangle . Also, find the cost of ploughing the field at Rs 18.80 per 10 m^2​

Answer 1

Step-by-step explanation:

Perimeter= 540m

s1+s2+s3= 540

let the sides be 25x, 17x, 12x.

25x+17x+12x=540

54x=540

x=540/54

×=10

s1=25x

=25×10=250m

s2=17x

=17×10=170m

s3=12x

=12×10=120m

Area= under root(s(s-s1)(s-s2)(s-s3))

s=(a+b+c)/2

s= (250+170+120)/2

s= 540/2

s= 270

Area= under root(270(270-250)(270-170)(270-120))

Area= under root(270×20×100×150)

Area= under root(81000000)

Area=9000m/s^2

cost of ploughing=area× cost

cost per 10m/s^2=18.80

cost per m/s^2= 18.80/10= 1.880

cost of ploughing=9000×1.880

=rs 16920

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