The perimeter of a triangular field is 540 m and its sides are in the ratio 25:17:12 . find the area of the field . also , find the cost of ploughing the field at ₹5m^2
Answers
GIVEN :
Perimeter of triangular field = 540m
Ratio of the three sides = 25:17:12
Let the ratio be x
Perimeter of traingle = Sum of three sides.
According to the problem,
25x + 17x + 12x = 540
54x = 540
x = 540/54
x = 10
Substitute x
25x = 25(10) = 250
17x = 17(10) = 170
12x = 12(10) = 120
The sides of the triangle are 250, 170, 120.
Area of triangle using Heron's formula
S = 250 + 170 + 120 / 2
S = 540/2
S = 270
Substitute S in the formula.
Therefore, the area of triangle = 9000m²
Cost of ploughing one m² field = ₹5
Cost of ploughing the total field :
= 9000 × 5
= ₹45000
Therefore, the cost of ploughing total field = ₹45000.
Answer:
rs.45000
Step-by-step explanation:
Given,
perimeter of triangular field = 540m
ratio of the sides = 25:17:12
let, The sides of the triangle are 25x, 17x and 12x
As we know,
Perimeter of triangle = Sum of all sides
Therefore,
25x+17x+12x = 540
54x = 540
x = 10
The first side of the triangle (a)= 25x
a = 25(10)
a = 250
The second side of the triangle (b) = 17x
b = 17(10)
b = 170
The third side of the triangle(c) = 12x
c = 12(10)
c = 120
Now, from heron's formula
_____________________________
To plough 1m^2, it costs rs. 5
cost for ploughing 900m is
= 5 × 9000
= 45000
Therefore,