Question

the perimeter of a triangular field is 540 metre and its sides are in ratio 25:17:12 . find the area of the triangle . also find the cost of cultivating the field at rupees 2460 per
100 metre square​

Answer 1

Step-by-step explanation:

HELLO DEAR,

GIVEN:- perimeter = 540m

and sides are in ratio 25:17:12

So, the sides are 25x , 17x , 12x where x is any positive no.

then ,25x + 17x + 12x = 540

54x = 540

x = 10

25x = 25 * 10 = 250

17x = 17*10 = 170

12x = 12*10 = 120

So, the sides are 250m , 170m & 120m.

now, the semi - perimeter is S = 540/2 = 270 m

we know the Heron's formula:-

area of triangle = $\sf{\sqrt{s(s - a)(s - b)(s - c)}} </p><p>s(s−a)(s−b)(s−c)$

where, a,b,c is the sides of triangle and s is the semi-perimeter.

now, the area of the triangle is

$= \sf{\sqrt{S(S - 250)(S - 170)(S - 120)}}$

$= \sf{\sqrt{270*(270 - 250)*(270 - 170)*(270 - 120)}}$

$= \sf{\sqrt{270*20*100*150}}$

$= \sf{\sqrt{81000000}}$

= 9000m²

Hence, the area of triangle = 9000m²

I HOPE ITS HELP YOU DEAR,

THANKS

Answer 2

Answer:

a = 25x

b.=17x

c=12x

Step-by-step explanation:

a+b+c+=perimeter

25x+17x+12x=540

54x =540

x= 540÷54=10

10×25=250

10×17=170

10×12=120

a+b+c÷1/2

250+170+120/2= 480

area

250- 480=-230

170-480= -130

120- 480= -360

[ s ( s-a)(s-b)(s-c) ]

(480 -230-130-360)= -240

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