Question

The perimeter of a triangular field is 540m and its sides are in the ratio 25:17:12. Find the area of the triangle. Also find the cost of ploughing the field at Rupees 18.80 per 10 m^2.

Plzz.....​

Answer 1

Answer:

let the sides be 25x,17x,12x

perimeter= 540m

25x+17x+12x=540m

54x=540

x=540/54

x= 10m

So sides will be 250m,170m,120m

Now

s= 250+170+120/2

= 540/2

= 270

Now by herons formula we have

area=√s(s-a)(s-b)(s-c)

= √270×20×100×150

= 9000m^2

cost of ploughing =9000×10/18.8

=900000/188

=₹ 4787.23

hope it helps you

please mark brainliest

Answer 2

Step-by-step explanation:

$\huge {\purple {\fbox {\bigstar {\mathfrak {\red {hello\:mate}}}}}}$

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$\huge {\purple {\fbox {\bigstar {\mathfrak {\red {ur\: question}}}}}}$

$\huge {\mathfrak {\purple {Q.}}}}$The perimeter of a triangular field is 540m and its sides are in the ratio 25:17:12. Find the area of the triangle. Also find the cost of ploughing the field at Rupees 18.80 per 10 m^2.

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$\huge {\purple {\fbox {\bigstar {\mathfrak {\red {ur\: ANSWER✓}}}}}}$

Step-by-step explanation:

Let the sides of the triangle be 25x, 17x and 12x

Given,

$Perimeter of the triangle = 540 m$

⇒ 540 = 25x + 17x + 12x

⇒ 540 = 54x

 $x =\frac{540}{54}$

$⇒ x=\cancel{100}/\cancel4$

⇒ $\huge{\blue{\fbox{\mathbf{\red{x=\:10}}}}}}}$

$\tt\red{\text{Thus, sides of the triangle are:}}$

⇒  25x = 25 × 10 = 250 m

⇒  17x = 17 × 10 = 170 m

⇒  12x = 12 × 10 = 120 m

Let,

$a = 250 m,$

$b = 170 m,$

$c = 120 m$

$\tt\red{\text{Therefore,}}$

=$\frac{a+b+c}{2}$

$s =  250 + 170 + \frac{120}{2}$

$s=\frac{250+170+120}{2}$

$s=\frac{540}{2}\cancel{540}/\cancel2$

$s=270$

$\huge{\blue{\fbox{\mathbf{\red{s=\:270}}}}}}}$

$\implies\huge\blue{\text{Therefore,}}$

 Area of triangle =

$\displaystyle \sqrt{[s(s - a)(s - b)(s - c)]}$

= $\displaystyle \sqrt{[270 (270 - 250)(270 - 170)(270 - 120)]}$

= $\displaystyle \sqrt{[3 × 3 × 3 × 10 × 10 × 2 × 10 × 10 × 10 × 5 × 3]}$

=3 × 3 × 10 × 10 × 10

$= 9×10^3$

$= 9000 m^3$

$\huge{\blue{\fbox{\purple{\bigstar{\mathbf{\red{answer=\:9000m^3}}}}}}}$

Cost of ploughing the field at the rate of Rs. 18.80 per 10 m²

=  $\frac{18.80}{10}$ × 9000

$\huge{\blue{\fbox{\purple{\bigstar{\mathbf{\red{answer=\:rs\:18.80}}}}}}}$

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$\huge{\blue{\purple{\mathbf{\red{hope\:it\:helps\:you}}}}}}}$