Question

The perimeter of a triangular field is 540m and its sides are in the ratio 25:17:12. Find the area of the triangle.

Answer 1

let x be the common multiple
perimeter = a+b+c
$540 = 25x + 17x + 12x \\ 540 = 54x \\ x = \frac{540}{54} \\ x = 10$
side 1= 25x = 250 m
side 2 = 17x = 170 m
side 3 = 12 x = 120m

Answer 2

hey! friend
let the angle be x
perimeter=540
25x+17x+12x=540
54x=540
x=540/54
x=10
so the sides =>
25x=250
17x=170
12x=120

area of triangle=A=hypotenuse*breath/2


put the value and u will get your answer.


hope it helps!!!!