Question

the perimeter of a triangular field is 540m and its sides are in the ratio 25:17:12.Find the area of the triangle. also find the cost of ploughing the field at Rs18. 80 per 10 m2​

Answer 1

Step-by-step explanation:

Consider a, b, c as the sides of a triangle in the ratio 25: 17: 12 It can be written as a: b: c = 25: 17: 12 So we get a = 25, b = 17 and c = 12 It is given that Perimeter = 540 m So we get 25x + 17x + 12x = 540 On further calculation 54x = 540 By division x = 10 By substituting the value of x a = 25x = 25(10) = 250m b = 17x = 17(10) = 170m c = 12x = 12(10) = 120m We know that Area = 9000m2 It is given that the cost of ploughing the field is ₹ 5 per m2 So the cost of ploughing 9000m2 = 5 × 9000 By multiplication The cost of ploughing 9000m2 = ₹ 45000 Therefore, the area of the field is 9000 mRead more on Sarthaks.com - https://www.sarthaks.com/719308/the-perimeter-triangular-field-540-and-its-sides-are-in-the-ratio-25-find-the-area-the-field?show=719315#a719315

Answer 2

Step-by-step explanation:

Perimeter of triangle =540m

Let the sides of triangle be,a, b and c,

On dividing 540 m in the ratio 25:17:12, we get

a=25xcm

b=17xcm

c=12xcm

we know that, perimeter of a triangle = Sum of all sides =a+b+c

540=25x+17x+12x

540=54x

x=10

Sides are:

a=25x=250cm

b=17x=170cm

c=12x=120cm

Let a, b and c be the sides of a triangle.

Apply Heron's Formula of find the area of triangle.

Area =

S(S−a)(S−b)(S−c)

Where S= 2a+b+c

S= 21

(250+170+120)=270m

Area = (270(270−250)(270−170)(270−120)

= (270×20×10×150) =9000

Area of triangle is 9000m

Now,

The cost of ploughing 100m

2=Rs40

The cost of ploughing 1m

=Rs

100

40

Therefore, cost of ploughing 9000m

2

=9000

)=Rs3600