the perimeter of a triangular field is 540meter and it's sides are in the ratio 25:17:12. find the area of the field also find the cost of ploughing the field at ₹5 per meter square
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25x+17x+12x=540; let x be a constant,
54x= 540
x=10
so the side lengths are 250, 170, 120.
The area of triangle by Heron's formula is
A=√(s*(s-a)*(s-b)*(s-c))
s= (a+b+c)/2
a=250 ; b= 170 ;c = 120
s = 540/2 = 270
Area = √(270*(270-250)*(270-170)*(270-120))
= √(270*20*100*150)
= √81000000
= 9000 square meter
cost of ploughing = 9000*5 = 45000/-
( 1 sq. mt = 5/- )
54x= 540
x=10
so the side lengths are 250, 170, 120.
The area of triangle by Heron's formula is
A=√(s*(s-a)*(s-b)*(s-c))
s= (a+b+c)/2
a=250 ; b= 170 ;c = 120
s = 540/2 = 270
Area = √(270*(270-250)*(270-170)*(270-120))
= √(270*20*100*150)
= √81000000
= 9000 square meter
cost of ploughing = 9000*5 = 45000/-
( 1 sq. mt = 5/- )
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