Question

The perimeter of a triangular ground is 420m and its sides are in the ratio 6:7:8.find the area of the triangular ground

Answer 1

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Answer 2

let it's sides be : 6x and 7x and 8x
now, 420=6x+7x+8x
420=21x
420/21=x
20=x
here, x=20
so, 6*20=120
7*20=140
8*20=160

to find its area we need to find its semi perimeter, 420/2=210

now, by using heron'S formula :
area of triangular ground = √s(s-a) (s-b) (s-c)
A = √210(210-120)(210-140)(210-160)
A = √210*90*70*50
A =√2*3*5*7*2*3*3*5*2*5*7*2*5*5
A=2*2*3*5*5*7√3*5
A=2100√6m^2
so, we have area of triangular ground is 2100√6m^2
if u want answer not in root so,
2100*2.48
= 5208m^2