Question

The perimeter of a triangular ground is 420m and its sides are in the ratio 6:7:8 . Find the area of the triangular ground. heron's method
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Answer 1

Answer:

Let sides of △ are=6x,7x and 8x

Perimeter=6x+7x+8x=21x

21x=410

x=20

Sides are 120,140 and 160 m

Area =

S(S−A)(S−B)(S−C)

[Heron's Formula]

S=

2

120+140+160

=210 m

A=

210(210−120)(210−140)(210−160)

=2100

15

sq. m

Answer 2

Step-by-step explanation:

let the side of triangle = 6x, 7x and 8x

perimeter of triangular ground= 420m

6x + 7x + 8x = 420

21x = 420

x = 420/21

x = 20

side = 6x, 7x, 8x

6x = 6× 20

=120

7x =7×20

=140

8x =8×20

=160

s =120+140+160/2

=420/2

=210

√210(210- 120)(210 -140)(210-160)

√210(90)(70)(50)

√66150000

= 8133•265 m^3