The perimeter of a triangular is 540 m and its sides are 25 : 17 : 12. Find the measurement each of its sides.
Answers
Answer:
Let the sides are 25x, 17x, 12 x
Perimeter of a A = sum of three sides
25x + 17x + 12x = 540
54x = 540
x = 10
1st side (a) - 25x = 25×10= 250m
2nd side(b)= 17x = 17×10= 170m
3rd side (c)= 12x = 12 x 10 =120m
Semi - perimeter (S) = a+b+c/2
= (250+ 170+120)/2 = 540/2 = 270 m
Area of the A= √ S(S-a)(S - b)(S - c)
[By Heron's Formula]
= √ S(S-250)(S-170)(S-120)
= √270(270 - 250)(270-170)(270-120)
= √270x 20×100×150
= √ 81000000
Area of the A= 9000 m²
Hence, the Area of the A= 9000 m²
Answer:
Let the sides are 25x, 17x, 12 x
Perimeter of a A = sum of three sides
25x + 17x + 12x = 540
54x = 540
x = 10
1st side (a) - 25x = 25×10= 250m
2nd side(b)= 17x = 17×10= 170m
3rd side (c)= 12x = 12 × 10 -120m
Semi - perimeter (S) = a+b+c/2 = (250+ 170+120)/2 = 540/2 = 270 m
Area of the A= √ S(S - a)(S - b)(S - c)
[By Heron's Formula]
= √ S(S-250)(S-170)(S-120)
= √ 270(270-250)(270-170)(270
= √270x 20×100×150
= √ 81000000
Area of the A= 9000 m²
Hence, the Area of the A= 9000 m²