Math, asked by sameervt2239, 9 months ago

The perimeter of a tringle is 5a²+5a+9 and the two sides are a²+2a-3 and 2a²+a-3. Find the third ans

Answers

Answered by jawanda05
0

Answer:

2a^2+2a+15

Step-by-step explanation:

we know here,

we know here,perimeter of triangle is 5a^2+5a+9.

we know here,perimeter of triangle is 5a^2+5a+9.one side=a^2+2a-3

we know here,perimeter of triangle is 5a^2+5a+9.one side=a^2+2a-3and, second one = 2a^2+a-3

we know here,perimeter of triangle is 5a^2+5a+9.one side=a^2+2a-3and, second one = 2a^2+a-3we also know that,

we know here,perimeter of triangle is 5a^2+5a+9.one side=a^2+2a-3and, second one = 2a^2+a-3we also know that,perimeter of triangle = sum of its three sides.

we know here,perimeter of triangle is 5a^2+5a+9.one side=a^2+2a-3and, second one = 2a^2+a-3we also know that,perimeter of triangle = sum of its three sides.let third side be 'x'.

we know here,perimeter of triangle is 5a^2+5a+9.one side=a^2+2a-3and, second one = 2a^2+a-3we also know that,perimeter of triangle = sum of its three sides.let third side be 'x'.now,

we know here,perimeter of triangle is 5a^2+5a+9.one side=a^2+2a-3and, second one = 2a^2+a-3we also know that,perimeter of triangle = sum of its three sides.let third side be 'x'.now,5a^2+5a+9 = (a^2+2a-3)+(2a^2+a-3)+x

we know here,perimeter of triangle is 5a^2+5a+9.one side=a^2+2a-3and, second one = 2a^2+a-3we also know that,perimeter of triangle = sum of its three sides.let third side be 'x'.now,5a^2+5a+9 = (a^2+2a-3)+(2a^2+a-3)+x5a^2+5a+9 = 3a^2+3a-6+x

we know here,perimeter of triangle is 5a^2+5a+9.one side=a^2+2a-3and, second one = 2a^2+a-3we also know that,perimeter of triangle = sum of its three sides.let third side be 'x'.now,5a^2+5a+9 = (a^2+2a-3)+(2a^2+a-3)+x5a^2+5a+9 = 3a^2+3a-6+x(5a^2+5a+9)-(3a^2+3a-6) = x

we know here,perimeter of triangle is 5a^2+5a+9.one side=a^2+2a-3and, second one = 2a^2+a-3we also know that,perimeter of triangle = sum of its three sides.let third side be 'x'.now,5a^2+5a+9 = (a^2+2a-3)+(2a^2+a-3)+x5a^2+5a+9 = 3a^2+3a-6+x(5a^2+5a+9)-(3a^2+3a-6) = x2a^2+2a+15 = x

thus, the third side is 2a^2+2a+15

hope it helped...

Answered by dhakedudit
0

Answer:

answer is 2a²-8a+15 ha man answer dado

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