The perimeter of ∆ABC in fig is _________.
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Answer:
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Answer:
36 cm
Step-by-step explanation:
Consider ∆ADC
AD=6cm
DC= 16/2 = 8cm
By Pythagoras theorem,
AC^2=AD^2+DC^2
= 6^2+8^2
= 36+64 = 100
AC = √100 = 10
AB = AC = 10
therefore, perimeter = 10+10+16= 36cm
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