Question

The perimeter of an equilateral tringle is 60 cm . find its area and height (given √3=1.732

Answer 1

Answer:

Perimeter of the given equilateral triangle = 60 cm. Length of each of its sides =603cm=20cm. =(100×1.732)cm2=173.2cm2. Hence, the area of the given triangle is 173.2 cm2.

this is your answer

Answer 2

Answer:

Area = 173.2 $cm^{2}$

Height = 17.32 cm

Step-by-step explanation:

Perimeter of the given equilateral triangle = 60 cm.

Length of each of its sides =$\frac{60}{3}$ cm=20cm.

Area of the triangle =(√3/4 ×$a^{2}$) sq units

=(√3/4×20×20)$cm^{2}$ =(100×√3)$cm^{2}$

=(100×1.732)$cm^{2}$ = 173.2$cm^{2}$

Hence, the area of the given triangle is 173.2 $cm^{2}$

Let the height of the given triangle be h cm.

Then,  its area=($\frac{1}{2}$ ×b×h)=(12×20×h)$cm^{2}$ .

∴ $\frac{1}{2}$ ×20×h=173.2

= h=$\frac{173.2}{10}$

height= 17.32cm.

Hence, the height of the given triangle is 17.32 cm.