The perimeter of an isoceles traingle is 27cm & the length of the congruent sides is greater than twi
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the side of triangle are 12 12 5
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Let th base be X
Then length of equal sides be = 2x+1
Perimeter of triangle = sum of all side
27 = X + 2X+1 +2X+1
27 = 5X +2
27-2 = 5X
25 = 5X
25/5 = X
5 = X (base)
Length of congruent side = 2x+1
= 2(5)+1
= 10+1
= 11
Therefore length of all side of triangle is 5, 11 and 11.
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Then length of equal sides be = 2x+1
Perimeter of triangle = sum of all side
27 = X + 2X+1 +2X+1
27 = 5X +2
27-2 = 5X
25 = 5X
25/5 = X
5 = X (base)
Length of congruent side = 2x+1
= 2(5)+1
= 10+1
= 11
Therefore length of all side of triangle is 5, 11 and 11.
If you satisfied mark it brainliest.
Remember, your support is encouragement for us (•_•).
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