Question

The perimeter of an isoceles triangle is 24cm.The length of its congruent sides is 13cm less than twice the length of its base. Find the lengths of all sides of the triangle ​

Answer 1

Step-by-step explanation:

let the length of the base of the isosceles triangle be X

Perimeter of isosceles triangle = 24cm

length of Congruent Side = 2x-13

LetAB and Ac are the congruent side

and BC is base.

Perimeter of the triangle = 24cm

AB + Ac+BC=24cm

2x-13+2x-13+x=24cm

5x-26=24cm

5x=24+26

5x=50cm

x = 10cm

AB = Ac=2x-13=2*10-13

=20-13cm

= 7cm

BC=X=10cm

Answer 2

Step-by-step explanation:

Given:-

• The perimeter of an isoceles triangle is 24cm.

• The length of its congruent sides is 13cm less than twice the length of its base.

To Find:-

• The lengths of all sides of the triangle.

Solution:-

Let the base of the isosceles triangle be x cm

As, The length of its congruent sides is 13cm less than twice the length of its base.

Length of congruent sides = 2( Base ) - 13

Length of congruent sides = 2x - 13

Given, perimeter of the triangle = 24cm

Perimeter of triangle = sum of all sides

→ 24 = x + (2x - 13) + (2x - 13)

→ 24 = x + 2x + 2x -13 -13

→ 24 = 5x - 16

→ 5x = 24 + 26

→ 5x = 50

→ x = $\dfrac{50}{5}$

→ x = 10

The base of the triangle = x = 10cm

The length of congruent sides

= 2x - 13

= 2 × 10 - 13

= 20 - 13

= 7cm

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