The perimeter of an isosceles right angled triangle is 2p unit. The area of the same triangle is
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Since the triangle is isosceles right, the sides are a,a and √2 a units.
Now perimeter is a+a+√2a = (2+√2)a (=2p)
So, a = 2p/(2+√2)
Now area = 1/2 * a * a
= 1/2 * (2p/(2+√2))²
= 2p²/(2+√2)²
= p²/(1+√2)²
= p²/(2√2 + 3) square unit
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Answer:
AC² = AB² + BC²
AC² = X² + X²
AC² = 2x²
AC² = √2x²
AC² = x√2
Step-by-step explanation:
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