The perimeter of an isosceles right triangle is 5(2+√2)cm. Its area is
(1) 5 cm²
(2) 10 cm²
(3) 12.5 cm²
(4) 25 cm²
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GIVEN: Isosceles Right triangle ABC right angled at B, AB = BC = a
So, hypotenuse AC = √(2a²) = √2a ( by Pythagoras law)
Hence, Perimeter = 2a +√2a
=> 2a + √2a = 5(2+√2)
=> a(2+√2) = 5 (2+√2)
=> a = 5
Hence area( triangle ABC) = (1/2) * BC * AB
=> area( tri ABC) = (1/2)*5*5 = 25/2 = 12.5
Area ( tri ABC) = 12.5 cm²
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