Question

The perimeter of an isosceles trapezium (having non-parallel sides equal) is 7.07 cm. If the parallel sides of the trapezium measure 37/20cm and 58/25cm, find the measure of the equal non-parallel sides.​

Answer 1

Assume a isosceles trapezium ABCD having, AB parallel to DC and AD = BC.

AB = 58/25 = 2.32 cm , CD = 37/20 = 1.85 cm

Perimeter of ABCD is 7.07 cm

AB + BC + CD + AA = 7.07cm

2.32 + BC + 1.85 + BC = 7.07

2BC + 4.17 = 7.07

2BC = 7.07 - 4.17

2BC = 2.9

BC = 2.9/2

BC = 29/20 cm and AD = 29/20 cm