The perimeter of an isosceles trapezium (having non-parallel sides equal) is 7.07 cm. If the parallel sides of the trapezium measure 37/20cm and 58/25cm, find the measure of the equal non-parallel sides...... Answer is 29/20 cm
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Assume a isosceles trapezium ABCD having, AB parallel to DC and AD = BC.
AB = 58/25 = 2.32 cm , CD = 37/20 = 1.85 cm
Perimeter of ABCD is 7.07 cm
AB + BC + CD + AA = 7.07cm
2.32 + BC + 1.85 + BC = 7.07
2BC + 4.17 = 7.07
2BC = 7.07 - 4.17
2BC = 2.9
BC = 2.9/2
BC = 29/20 cm
29/20 cm is the measure of the equal non-parallel sides
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