Math, asked by MohitS7, 1 year ago

The perimeter of an isosceles trapezium is 134 cm and the bases

are 54 cm and 30 cm in length. Find the length of the non parallel

sides of the trapezium and its area.

Answers

Answered by prajapatyk
49
perimeter of trapezium=134cm
let the trapezium be ABCD in which AB and CD are parallel sides and AD and BC are non parallel sides.
then AB=54cm and CD=30cm
AD=BC
perimeter of trapezium=134cm
AB+BC+CD+AD=134
AD+AD+54+30=134
2AD=50
AD=25cm
Hence non parallel sides which are of equal length =25cm
Answered by swathika23
23
as it is a isoceles trapezium,both the non parallel sides are equal.
perimeter of trapezium = side (1 +2+ 3 + 4) ------------1
we know the non parallel sides (2 and 4 )are equal
2 = 4 -----------2 
let sides 2 and 4 be x

substituting 2 in 1,
134 = 54 + 30 + 2 + 4
134 = 84 + 2 (x)
50 = 2x
x=25
thus sides 2 and 4 = 25cm 

area of trapezium = (sum of non parallel sides )h/2
= 25 + 25 h/2
=50h/2
=25h

hope it helps!!!!

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