Question

The perimeter of an isosceles triange is 24cm. The length of its congruent side is 13 less than twice the length of its base .Find the length of all sides

Answer 1

Solution:-

Let the base be x cm.

=> The Other Two sides = 2x - 13 cm

PERIMETER of ISOSCELES Triangle = 24cm.

=> (2x - 13) + (2x - 13) + x = 24

=> 5x - 26 = 24

=> 5x = 50

=> x = 10 cm.

Hence,

Base = 10cm.

Other Two sides = 2 × 10 - 13
=> 20 - 13
=> 7 cm.

Answer 2

Hii friend,

Let ∆ABC be an isosceles triangle.

In which,

BC be a base and AB , AC be the two congruent sides of ∆ABC.

Let the length of base BC of an isosceles triangle be X cm.

Then the length of congruent sides AB and AC = (2X-13)

LENGTH of it's two congruent side is 2(2X -13) = 4X -26

AB + AC = 4X-26

Perimeter of triangle = 24

AB + AC + BC = 25

(4X -26+ X) = 24

5X = 24+26

5X = 50

X = 50/5

X = 10

Length of base of an isosceles triangle = X = 10 cm

And,

The Length of it's congruent sides = 2X -13 = 2 × 10 -13 = 20 - 13 = 7 cm

HOPE IT WILL HELP YOU..... :-)

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