Math, asked by manavmehta1304p9jfk0, 1 year ago

The perimeter of an isosceles triangle 32 cm. The ratio of the equal side to its base is 3:2. Find the area of triangle.

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Answers

Answered by BrainlyPrincess
1
the perimeter of isosceles triangle = 32cm
p of isosceles triangle = 2 * equal side + base
let length of equal side be 3x and base be 2x
then
2 * 3x + 2x = 32 cm
6x + 2x = 32cm
8x = 32 cm
x= 4 cm
length of equal side = 3*4= 12cm
length of base = 2*4=8cm
area of isosceles triangle=b*1/4*√4a2-b2
= 8*1/4√4*144-64
=2√512
=2*22.62
= 45.25cm2

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