the perimeter of an isosceles triangle is 103/4cm. if one of its equal sides is 25/6cm. find the third side
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Answered by
4
Each equal side = 25/6 cm
Let other side be= x cm
Perimeter of triangle = 103/4 cm
25/6 + 25/6 + x = 103/4
50/6 +x = 103/4
x = 103/4 - 50/6
x = 309 - 100/12
x = 209/12
OR x = 17.42 cm (approx.)
Hence, the third side is 209/12 cm
Let other side be= x cm
Perimeter of triangle = 103/4 cm
25/6 + 25/6 + x = 103/4
50/6 +x = 103/4
x = 103/4 - 50/6
x = 309 - 100/12
x = 209/12
OR x = 17.42 cm (approx.)
Hence, the third side is 209/12 cm
Answered by
3
Each equal side length = 25/6 cm
Let third side be 'x'
Perimeter of isoscales triangle=103/4 cm
25/6+25/6+x=103/4
50/6+x=103/4
x=103/4 - 50/6
x=103/4×3/3 - 50/6×2/2
x=309/12-100/12
x=(309-100)/12
x=209/12 cm
Therefore,the length of third side is 209/12 cm
Hope it helps
Let third side be 'x'
Perimeter of isoscales triangle=103/4 cm
25/6+25/6+x=103/4
50/6+x=103/4
x=103/4 - 50/6
x=103/4×3/3 - 50/6×2/2
x=309/12-100/12
x=(309-100)/12
x=209/12 cm
Therefore,the length of third side is 209/12 cm
Hope it helps
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