the perimeter of an isosceles triangle is 117/14cm. if its unequal side measures 7/2cm,find the measure of its equal sides.
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Answered by
13
measure of its equal side is 17/7 each
as unequal side measures 7/2
then,
(117/14-7/2)÷2=(68/14)÷2
=17/7
as unequal side measures 7/2
then,
(117/14-7/2)÷2=(68/14)÷2
=17/7
Answered by
14
we know that
p=117/14
unequal =7/2
then,
two angles are equal in isosceles triangle
so, 7/2+x+x=117/14
2x=117/14-7/2
=68/14=34/7
x=34/7/2
=34/7*1/2=17/7
it is right bro mark as brainliest plezzzzzzz
p=117/14
unequal =7/2
then,
two angles are equal in isosceles triangle
so, 7/2+x+x=117/14
2x=117/14-7/2
=68/14=34/7
x=34/7/2
=34/7*1/2=17/7
it is right bro mark as brainliest plezzzzzzz
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