The perimeter of an isosceles triangle is 16 cm if each of the equal sides is 6 cm Then what is the length of it's base?
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Perimeter of triangle=16cm
Length of equal side=6cm
So, perimeter of the triangle = 16 cm
Side + side + side = 16
6 + 6 + side =16
12 + side = 16
Side = 16 - 12
Side = 4
So, the length of the base = 4 cm
Length of equal side=6cm
So, perimeter of the triangle = 16 cm
Side + side + side = 16
6 + 6 + side =16
12 + side = 16
Side = 16 - 12
Side = 4
So, the length of the base = 4 cm
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hello users ...
solution:-
let the Base of isosceles triangle = x cm
According to given:
perimeter of triangle
= sum of length of all sides of triangle = 16 cm
=> 6 + 6 + x = 16 cm
=> x + 12 = 16 cm
=> x = 16 - 12 = 4 cm
=> Base of triangle = 4 cm Answer
# hope it helps :)
solution:-
let the Base of isosceles triangle = x cm
According to given:
perimeter of triangle
= sum of length of all sides of triangle = 16 cm
=> 6 + 6 + x = 16 cm
=> x + 12 = 16 cm
=> x = 16 - 12 = 4 cm
=> Base of triangle = 4 cm Answer
# hope it helps :)
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