Question

the perimeter of an isosceles triangle is 18 cm if one of the equal side is 20 3 upon 4 cm find the measure of the third Prime third side​

Answer 1

Correct question: The perimeter of an isosceles triangle is 18 cm. If one of the equal side is 23/4 cm. Find the measure of the third side.

Answer:

$\large{\underline{\boxed{\sf \dfrac{13}{2}}}}$

Step-by-step explanation:

Given that ;

On equal side is $\sf \dfrac{23}{4}$ cm.

Let the third side of the isosceles triangle be x cm.

According to the question ;

Perimeter of triangle = 18 cm

⇒ 2 * (equal side) + third side = 18 cm

⇒ 2 * $\sf \dfrac{23 }{4}$ + x =18

⇒ $\sf \dfrac{23}{2}$ + x = 18

⇒ x = 18 - $\sf \dfrac{23}{2}$

⇒ x = $\sf \dfrac{36 - 23}{2}$

⇒ x = $\sf \dfrac{13}{2}$

Hence, the third side of the isosceles triangle is $\bf \dfrac{13}{2}$ cm.

_______________________

$\large{\underline{\underline{\mathfrak{\heartsuit \: Extra \: Information: \: \heartsuit}}}}$

In isosceles triangle, two sides are equal.

Also, the perimeter of triangle is the sum of all sides.

Answer 2

$\mathfrak{\blue{\underline{\underline{Question}}}}$

The perimeter of an isosceles triangle is 18 cm if one of the equal side is 23/4 cm find the measure of the third side.

$\mathfrak{\blue{\underline{\underline{Answer}}}}$

$\boxed{\dfrac{13}{2}}$

$\mathfrak{\blue{\underline{\underline{Step\: By\: Srep\: Solution}}}}$

Given:

Perimeter of triangle = 18 cm

Length of each of the equal side(in centimetre) = $\dfrac{23}{4}$

Let the third side be x

We know,

$\boxed{Perimeter \:of \: Triangle = Sum \:of\: all\: Sides}$

Here,

$18 = 2 \times \dfrac{23}{4} + x \\ \implies 18 = \dfrac{23}{2} + x \\ \implies x = 18 - \dfrac{23}{2} \\ \implies x = \dfrac{36 - 23}{2} \\ \implies x = \dfrac{13}{2}$