Question

the perimeter of an isosceles triangle is 24cm one of the non equal side is 4cm , find the area of triangle please need step by step answer please answer it please please please please​

Answer 1

Answer:

Step-by-step explanation:

Let the equal side of ∆ be (x) m

x+x+4=24

2x=20

x=10m

S=perimetre/2

=12

Using heron's formula,area of ∆=

[s(s-a)(s-b)(s-c)]^1/2

[12(12-10)(12-10)(12-4)]^1/2

(4×3×4×2×4)^1/2

8√6

So,area of the given ∆ is 8√6 m^2

Answer 2

Answer:

Perimeter = 24cm( In isosceles triangle two sides are equal)

one of the non equal side is 4cm.

So 24-4=20(Length of the two equal sides)

so length of one equal side is

20÷2=10cm.

The area of triangle suggested by heron's formulae

semi-perimeter=10+10+4÷2=12cm

• Area of triangle=

$\sqrt{s(s - a)(s - b)(s - c) }$

where a,b,c are the sides of triangle so

$\sqrt{12(12 - 10)(12 - 10)(12 - 4)}$

$\sqrt{12(2)(2)(8)}$

$\sqrt{2 \times 2 \times 3 \times 2 \times 2 \times 2 \times 2 \times 2}$

$2 \times 2 \times 2 \sqrt{3 \times 2}$

$8 \sqrt{6}$

area of triangle=

$8 \sqrt{6}$