The perimeter of an isosceles triangle is 28 cm. Each of the equal sides is 8 cm. Find the third side
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Let ∆ABC be an isosceles triangle, where AB = 8 cm Case I: If AB = BC AB = BC = 8 cm Perimeter of the triangle ABC = 28 cm ⇒ AB + BC + CA = 28 cm ⇒ 8 cm + 8 cm + CA = 28 cm ⇒ 16 cm + CA = 28 cm ⇒ CA = 28 cm – 16 cm = 12 cm ∴ Sides are 8 cm, 8 cm and 12 cm Case II: If BC = CA Perimeter of the triangle ABC = 28 cm ⇒ AB + BC + CA = 28 cm 8 cm + 2BC = 28 cm ⇒ 2BC = 28 cm – 8cm = 20 cm ⇒ BC = 10 cm ∴ Sides are 10 cm, 10 cm and 8 cm
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