Question

The perimeter of an isosceles triangle is 32 cm and the length of each equal side is 10 cm. Find the length of its base.

Answer 1

Answer:

l + l + l = 32

10+10+x= 32

20+x=32

x=32-20

x=12

Answer 2

$12 \: cm$

Step-by-step explanation:

$Given, \: \: perimeter = 32 \: cm \: \: \: and \\ length \: \: of \: \: each \: \: equal \: \: side = 10 \: cm \\ Let, \: \: \: the \: \: length \: \: of \: \: base = x \\we \: \: know \: \: \boxed{perimeter =sum \: \: of \: \: all \: \: sides } \\ then, \: \: \: \: 32 \: cm = 10 \:cm+ 10 \: cm+ x \\ 32 \: cm = 20 \: cm + x \\ x = 32 \: cm - 20 \: cm \\ x = 12 \: cm \\ So, \: \: the \: \: length \: \: of \: \: base = 12 \: cm$