the perimeter of an isosceles triangle is 32 cm.one of the equal sides is 10 cm.find the measure of remaining sides?
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Answered by
24
let the third side be x.
the 2 equal sides are 10cm,10cm.
perimeter=32cm
10+10+x=32
20+x=32
x=32-20
x=12cm
the sides are 10cm,10cm,12cm.
the 2 equal sides are 10cm,10cm.
perimeter=32cm
10+10+x=32
20+x=32
x=32-20
x=12cm
the sides are 10cm,10cm,12cm.
Answered by
10
let the third side be x cm
second side is equal to first side because it is an isosceles triangle
so the both are 10 cm
perimeter is 32 cm
perimeter= first side+second + third
32=10+10+x
32=20+x
x=32-20
x=12cm
the remaining two sides are 10 cm and 12 cm
hope this will help you
Mark as a brainliest
second side is equal to first side because it is an isosceles triangle
so the both are 10 cm
perimeter is 32 cm
perimeter= first side+second + third
32=10+10+x
32=20+x
x=32-20
x=12cm
the remaining two sides are 10 cm and 12 cm
hope this will help you
Mark as a brainliest
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