Question

The perimeter of an isosceles triangle is 32 cm.
The base is 2 cm more than the equal side. Find
the area of the triangle.​

Answer 1

Answer:

Area of triangle = 48 sq cm

Step-by-step explanation:

Let the equal sides of the isosceles triangle in cm = x

=> base = x + 2

Perimeter = 2(equal sides) + base

=> 2x + (x + 2) = 32

=> 3x + 2 = 32

=> 3x = 30

=> x = 10

The equal side of the isosceles triangle = 10cm

We can find area of the triangle using Heron's formula

Perimeter of triangle = 32

S = half perimeter = 16

$S_{1}$ = 10

$S_{2}$ = 10

$S_{3}$ = 12

Area = $\sqrt{S(S-S_{1})(S-S_{2})(S-S_{3} )}$

Area = √(16(6)(6)(4))

Area = √4²*6²*2²

Area = 4*6*2

Area = 48 sq cm

Answer 2

Here is your answer user.