Question

The perimeter of an isosceles triangle is 32 cm the ratio of the equal sides to its base is 3:2find the area of the triangle

Answer 1

Let the sides be 3x,3x,2x
3x + 3x+ 2x = 32
8x = 32
x = 4
Therefore sides are 12,12,8
semi perimeter = 16
Area = $\sqrt{16(16-12)(16-12)(16-8)}$
$=\sqrt{16(4)(4)(8)}$
        = 32√2 cm²

Answer 2

hey mate here is your answer.