Math, asked by yashika7555, 4 months ago

The Perimeter of An Isosceles triangle is 32 cm. The Ratio of the equal site to this base in 3:2 Find the area of the triangle​

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Answers

Answered by xGUITARx
0

Answer:

Please refer the above attachment

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Answered by dashingvansh581
0

Answer:

32√2cm²

Step-by-step explanation:

According to the question,

Perimeter of the isosceles triangle = 32 cm

It is also given that,

Ratio of equal side to base = 3 : 2 Let the equal side = 3x So, base = 2x Perimeter of the triangle = 32 ⇒ 3x + 3x + 2x = 32 ⇒ 8x = 32 ⇒ x = 4.

Equal side = 3x = 3×4 = 12 Base = 2x = 2×4 = 8 The sides of the triangle = 12cm, 12cm and 8cm. Let a = 12, b = 12, c = 8 s = (a + b + c)/2 ⇒ s = (12 + 12 + 8)/2 = 32/2 = 16.

Area of the triangle =

Area of the triangle = √s(s-a)(s-b)(s-c) = √16(16-12)(16-12)(16-8) = √16×4×4×8 = 32√2 cm²

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