Question

the perimeter of an isosceles triangle is 32 cm . the ratio of the equal side to its base is 3:2 find the area of the triangle​

Answer 1

Step-by-step explanation:

i hope this is helpful for you

Answer 2

Answer:

given:

perimeter of triangle: 32cm

let the sides be 3x, 2x and 3x

perimeter=sides

32= 3x+3x+2x

32=8x

x=4cm

therefore,

3x=3×4

=12cm^2 [repeat it once more timrsince the digit is same,]

2x=2×4

=8cm

the sides are now: 8+12+12

now,

sepmiperiter= 8+12+12/2

=16cm

thus area =

$\sqrt{16(16 - 12)(16 - 12)(16 - 8)}$

$= 16(4)(4)(8)$

$= 32 \sqrt{2} cm {}^{2}$