Question

the perimeter of an isosceles triangle is 32 cm . the ratio of the equal side to its base is 3:2 find the area of the triangle

Answer 1

the perimeter of isosceles triangle = 32cm
p of isosceles triangle = 2 * equal side + base
let length of equal side be 3x and base be 2x
then
2 * 3x + 2x = 32 cm
6x + 2x = 32cm
8x = 32 cm
x= 4 cm
length of equal side = 3*4= 12cm
length of base = 2*4=8cm
area of isosceles triangle=b*1/4*√4a2-b2
= 8*1/4√4*144-64
=2√512
=2*22.62
= 45.25cm2

Answer 2

Answer:

Step-by-step explanation:

Let the sides be 3x,3x,2x

3x + 3x+ 2x = 32

8x = 32

x = 4

Therefore sides are 12,12,8

semi perimeter = 16

Area = \sqrt{16(16-12)(16-12)(16-8)}

=\sqrt{16(4)(4)(8)}

= 32√2 cm²

Hope it helped you

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